Source code for NiaPy.benchmarks.trid

# encoding=utf8

"""Implementations of Levy function."""

from NiaPy.benchmarks.benchmark import Benchmark

__all__ = ['Trid']

[docs]class Trid(Benchmark): r"""Implementations of Trid functions. Date: 2018 Author: Klemen Berkovič License: MIT Function: **Levy Function** :math:`f(\textbf{x}) = \sum_{i = 1}^D \left( x_i - 1 \right)^2 - \sum_{i = 2}^D x_i x_{i - 1}` **Input domain:** The function can be defined on any input domain but it is usually evaluated on the hypercube :math:`x_i ∈ [-D^2, D^2]`, for all :math:`i = 1, 2,..., D`. **Global minimum:** :math:`f(\textbf{x}^*) = \frac{-D(D + 4)(D - 1)}{6}` at :math:`\textbf{x}^* = (1 (D + 1 - 1), \cdots , i (D + 1 - i) , \cdots , D (D + 1 - D))` LaTeX formats: Inline: $f(\textbf{x}) = \sum_{i = 1}^D \left( x_i - 1 \right)^2 - \sum_{i = 2}^D x_i x_{i - 1}$ Equation: \begin{equation} f(\textbf{x}) = \sum_{i = 1}^D \left( x_i - 1 \right)^2 - \sum_{i = 2}^D x_i x_{i - 1} \end{equation} Domain: $-D^2 \leq x_i \leq D^2$ Reference: https://www.sfu.ca/~ssurjano/trid.html """ Name = ['Trid']
[docs] def __init__(self, D=2): r"""Initialize of Trid benchmark. Args: Lower (Optional[float]): Lower bound of problem. Upper (Optional[float]): Upper bound of problem. See Also: :func:`NiaPy.benchmarks.Benchmark.__init__` """ Benchmark.__init__(self, -(D ** 2), D ** 2)
[docs] @staticmethod def latex_code(): r"""Return the latex code of the problem. Returns: str: Latex code """ return r'''$f(\textbf{x}) = \sum_{i = 1}^D \left( x_i - 1 \right)^2 - \sum_{i = 2}^D x_i x_{i - 1}$'''
[docs] def function(self): r"""Return benchmark evaluation function. Returns: Callable[[int, Union[int, float, List[int, float], numpy.ndarray]], float]: Fitness function """ def f(D, X): r"""Fitness function. Args: D (int): Dimensionality of the problem X (Union[int, float, List[int, float], numpy.ndarray]): Solution to check. Returns: float: Fitness value for the solution. """ v1, v2 = 0.0, 0.0 for i in range(D): v1 += (X[i] - 1) ** 2 for i in range(1, D): v2 += X[i] * X[i - 1] return v1 - v2 return f
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